Re: The Mysical Straight -8
Posted by Thomas Wilcox On 2008/6/12 1:34:54
I hate to be a nerd, but I am...so, a programmer would right the forumula as:
(pi/4)*bore^2*stroke*cylinders
where the ^ stands for power of, thus bore^2 is bore to the power of two.
Sincerely,
Your local friendly nerd that can't sleep
.
(pi/4)*bore^2*stroke*cylinders
where the ^ stands for power of, thus bore^2 is bore to the power of two.
Sincerely,
Your local friendly nerd that can't sleep
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