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The 200 made it back to my brother in law's house, so he can continue working on it. I continue to be amazed at how quiet the engine is. I sometimes have to glance at the oil pressure gauge to make sure it's still running.



The temp sender in the engine before wasn't working. So we had installed a new one when we rebuilt the valves, as well as a new 160 thermostat. The engine seems to run warm, which I'm assuming is due to the radiator. Probably needs to be boiled out. But the gauge seems to read higher than others.



Back of the water jacket



Top of head



Upper radiator tank



His plan is to remove the radiator and have it boiled out. No leaks right now, so hopefully none get opened up when it's cleaned.

If cleaning the radiator doesn't help with the high temp reading, the car may be one of those with a high reading temp gauge. This is the only article I remember seeing that addressed that issue. The Packard service fix of a "temperature gauge regulator" was nothing more than an added resistor in the power supply feed to the gauge in order to lower the gauge voltage and reading. Unfortunately Packard never provided a number so I have no idea what the resistor value was.

You might look and see if you have the regulator fix which could mean the new sender is most likely the issue. With a resistor in the circuit it needs to be the original type sender so the replacement might now be incorrect. Of course, finding the correct sender for use with the regulator would probably be next to impossible but if you don't have the service fix or even if you do, there might be a chance of adding or changing to a different resistor to bring the gauge more in line with what you have'

If you do have a resistor, it is probably a fairly low value so an ordinary ohmmeter would not likely give an accurate enough reading but it might be worth a try. The resistor is in a protective insulating sleeve but if it could be exposed to check to see if the resistor has any color bands or printing still visible we could probably figure out the value and go from there.